400-600-1123
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答案：
E
每一个偶
P是最小的质因数h(100）+1 p=
f(100)+1= (2 * 1) * (2 * 2) * (2 * 3) *（2*4） ... 8*(2 * 50)+1=（1*2*3*4...*50）X2^50+1=2*A+1=3*B+1=4*C+1=5*D+1....=50*x+1,所以，f(100)+1/2余数是1，/3余数为1，等等，/50余数也为1，即它们都不可以被2-50之间的数字整除
约数肯定也大于50.
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